Jannik Sinner has now won his last 19 matches in a row against Top 10 players other than Carlos Alcaraz

Jannik Sinner is into the final of the China Open in Beijing after battling past Alex de Minaur in the semifinals of the ATP 500 event on Tuesday, 6-3, 4-6, 6-2.

With that victory, Sinner maintained his perfect career record against De Minaur, improving to 11-0 lifetime against the tenacious Australian.

But there's an even bigger picture domination growing, too: Sinner has now won his last 19 matches in a row against Top 10 players other than Carlos Alcaraz, a stretch that dates back to the Masters 1000 event in Canada last year, where he fell to then-No. 8 Andrey Rublev in the quarterfinals. Since then, he's 1-5 against Alcaraz and 19-0 against all other Top 10 opposition.

De Minaur did snap one streak on Tuesday, though—by winning the second set, he ended Sinner's run of 39 sets in a row against Top 10 players other than Alcaraz. The last one the Italian had lost before this came to Daniil Medvedev in the quarterfinals of last year's US Open (he still won, 6-2, 1-6, 6-1, 6-4).

SINNER VS TOP 10 PLAYERS OTHER THAN ALCARAZ SINCE '24 CINCINNATI: 19-0

• d. No. 6 Rublev in '24 Cincinnati QFs, 4-6, 7-5, 6-4
• d. No. 4 Zverev in '24 Cincinnati SFs, 7-6, 5-7, 7-6
• d. No. 5 Medvedev in '24 US Open QFs, 6-2, 1-6, 6-1, 6-4
• d. No. 5 Medvedev in '24 Shanghai QFs, 6-1, 6-4
• d. No. 4 Djokovic in '24 Shanghai F, 7-6, 6-3
• d. No. 9 De Minaur in '24 ATP Finals RR, 6-3, 6-4
• d. No. 5 Fritz in '24 ATP Finals RR, 6-4, 6-4
• d. No. 4 Medvedev in '24 ATP Finals RR, 6-3, 6-4
• d. No. 7 Ruud in '24 ATP Finals SFs, 6-1, 6-2
• d. No. 5 Fritz in '24 ATP Finals F, 6-4, 6-4
• d. No. 9 De Minaur in '24 Davis Cup SFs, 6-3, 6-4
• d. No. 8 De Minaur in '25 Australian Open QFs, 6-3, 6-2, 6-1
• d. No. 2 Zverev in '25 Australian Open F, 6-3, 7-6, 6-3
• d. No. 7 Ruud in '25 Rome QFs, 6-0, 6-1
• d. No. 6 Djokovic in '25 Roland Garros SFs, 6-4, 7-5, 7-6
• d. No. 10 Shelton in '25 Wimbledon QFs, 7-6, 6-4, 6-4
• d. No. 6 Djokovic in '25 Wimbledon SFs, 6-3, 6-3, 6-4
• d. No. 10 Musetti in '25 US Open QFs, 6-1, 6-4, 6-2
• d. No. 8 De Minaur in '25 Beijing SFs, 6-3, 4-6, 6-2

Not only had Sinner won all 10 of his previous meetings against De Minaur, he had won their last 20 sets in a row, too—and he made that 21 in a row with a routine first set in Beijing on Tuesday. But De Minaur had other plans—after nine straight holds to start the second set, he pounced in the 10th game, breaking Sinner for the first time to send the match to a decider.

De Minaur finished the second set with 11 winners to 8 unforced errors, while Sinner's game went awry, producing 10 winners to 20 unforced errors.

But the Italian snapped right back into it from the start of the third set, breaking at love in the opening game and eventually building a 4-0, double-break lead in just 20 minutes. The two then held from there until it was over.

"I felt like it was a very high level," Sinner said. "We had many great rallies and many chances both ways—I had my chances in the second set and couldn't use them, and also he had more chances, so it was quite an even match.

"In the third set I tried to raise my level, and I broke him early, which gave me confidence serving against him for the rest of the set. I'm happy about today and obviously very happy to be back in the final here in Beijing."

Sinner also hit a big milestone on Tuesday: he's now through to the 30th tour-level final of his career. He's an impressive 20-9 in his first 29.

Standing between the No. 1-seeded Italian and his 21st career title in the Chinese capital will be either No. 8-seeded Medvedev or unseeded American Learner Tien, who played the second semifinal of the day.